In two first order simultaneous reactions A --> B & A --> C, where beginning A concentration C0 0.1 0.5 1 1.5 2 5 mol/dm3, with given k1, value as 0.1 0.2 0.5 1 2 1/s, and k2 0.1 0.2 0.5 1 2 1/s, calculate the molar concentration of substrate for every second of reaction for 5 10 15 20 30 40 50 60 s. For above give parameters calculate also changes of substrates B and C concentrations.

Answer

To calculate the progress of reaction, and, the concentration of substrate A and products B and C change, we will use the following formula:

where k1 - A --> B rate constant[1/s],k2 - A --> C rate constant[1/s], t -time [s], C0 - starting concentration[mol/dm3]

Then, for every second ( starting from 0) as t value, and for k1 and k2 putting 1/s and 1/s, we can calculate the concentrations value over time.

Take few k-values from the list and observe, that the higher k-value is, the faster our A concentration drops, means - the faster process goes from A ---> products.

Time	[s]	[A]	[mol/dm3]	Conc A over the time	[B]	[mol/dm3]	Conc B over the time	[C]	[mol/dm3]	Conc C over the time
0	s	0	mol/dm3		NAN	mol/dm3		NAN	mol/dm3